If an exposure monitor reads 700 mR at 3 meters from a fluoroscopic table, what will be the exposure to a technologist standing 2.5 meters away?

To determine the exposure a technologist standing 2.5 meters away from the fluoroscopic table would experience when the exposure monitor reads 700 mR at 3 meters, it's essential to apply the principles of the inverse square law. The inverse square law states that the intensity of radiation exposure is inversely proportional to the square of the distance from the source.

The exposure at 3 meters is given as 700 mR. If we want to find out the exposure at 2.5 meters, we can set up the relationship using the formula:

[ I_1/I_2 = (D_2^2)/(D_1^2) ]

Where ( I_1 ) is the initial intensity (700 mR), ( D_1 ) is the initial distance (3 m), ( I_2 ) is the intensity at the new distance (2.5 m), and ( D_2 ) is the new distance (2.5 m). Rearranging the formula allows us to solve for ( I_2 ):

[ I_2 = I_1 \times (D_1^2/D_2^2) ]

Plugging in the values:

[ I_2