When 350 volts are supplied to a transformer with specific turns, what is the voltage exiting the transformer?

To determine the voltage exiting a transformer when provided with a specific input voltage, it is essential to understand how a transformer operates in terms of its turns ratio. The voltage across the primary and secondary coils of a transformer is related to the number of turns in each coil. The basic relationship can be represented by the formula:

[ V_s / V_p = N_s / N_p ]

Where:

• ( V_s ) is the secondary voltage (outgoing)
• ( V_p ) is the primary voltage (incoming)
• ( N_s ) is the number of turns in the secondary winding
• ( N_p ) is the number of turns in the primary winding

Assuming that the transformer is designed to step up the voltage and you are given an input voltage of 350 volts (the primary voltage), you need to know the turns ratio to calculate the secondary voltage. If the turns ratio is correct, it can be deduced that the transformer significantly increases the input voltage to 1050 volts as the exit.

In the context of this question, if the voltage exiting the transformer is given as 1050 volts, it indicates a particular relationship in the turns ratio that allows this increase in voltage, which demonstrates the operational principle